如果像这样的会话中的条件，访问页面的正确语法是什么？

excuse me I have little problem what is right syntax to access page if I have condition like this (status) in session if status=0 and 2 can be access pegawai

this if status=0,

<?php if($this->session->userdata('STATUS')==0) {?> <li><a href="<?php echo base_url() ?>pegawai"><i class="icon-user"></i>Pegawai</a></li><?php } ?>

so I want this page can be access if status 0 and 2 what syntax that should be used?

I have make this

<?php 
if($this->session->userdata('STATUS')==0) {
?> 
    <li><a href="<?php echo base_url() ?>pegawai"><i class="icon-user"></i>Pegawai</a></li>
<?php 
} 
?>
<?php 
if($this->session->userdata('STATUS')==2) {
?> 
    <li><a href="<?php echo base_url() ?>pegawai"><i class="icon-user"></i>Pegawai</a></li>
<?php 
} 
?>

so if status 0 and 2 can be acces but it's not efficient

Are you asking how to use an Or logical operator?

<?php if($this->session->userdata('STATUS')==0 || $this->session->userdata('STATUS')==2): ?> 
    <li><a href="<?php echo base_url() ?>pegawai"><i class="icon-user"></i>Pegawai</a></li>
<?php endif; ?>

Answering but also down-voting this and suggesting you close it. Shows a lack of searching for the answer. You might want to read an intro to coding PHP.

Make it simpler like this

<?php
if( $this->session->userdata('STATUS')==0 || $this->session->userdata('STATUS')==2) {
?>
    <li><a href="<?php echo base_url() ?>pegawai"><i class="icon-user"></i>Pegawai</a></li>
<?php
}
?>