Foreach语法问题已经使用了不同项目中的代码现已破解[关闭]

So my problem is I do not understand why I am getting this error as I have used this code previously for a different task and it worked. Here is the sample code:

  <?php

  include('assets/php/sql/con.php');

  if (isset($_GET['age'])) {
    $AGE = $_GET['age'];
    $GENDER = $_GET['gender'];

      $results = DB::query('SELECT * FROM gift_db WHERE age =:age',array(':age' => $_GET['age']))[0]['age'];

      // DB::query('SELECT * FROM gift_db WHERE age=:age', array(':age'=>$_GET['age']));
      $allResults = "";
      foreach ($results as $r) {

        $allResults = $r;

    }
  }
   ?>

If anyone would be able to help out that would be amazing. Thanks :)

When use query function this function returned an array but you selected the first element of this array.

$results = DB::query('SELECT * FROM gift_db WHERE age =:age',array(':age' => $_GET['age']))[0]['age'];

Can you try with:

$results = DB::query('SELECT * FROM gift_db WHERE age =:age',array(':age' => (int) $AGE));

It's possible in your code insert any value on age.

PD:Sorry for my English

It seems like $AGE is coming as a string, not an integer, so can you please try like below:-

$results = DB::query('SELECT * FROM gift_db WHERE age =:age',array(':age' => (int) $AGE));