After about a week of research with no solution, I give up and I ask you guys for suggestions.
I need the same php script to handle POST requests in the same way, regardless of their origin which is either a simple HTML form, or an iOS app. No JSON involved.
Issue: Some chars are lost when the POST sender is the iOS app. At this point I would say that I don't know why it behaves like that. Apparently the web browser escapes all the chars correctly in the build up of the POST request, while my obj-c code does not.
In the objective-c code you can see 5 of the tentatives I did, with a little note of what went wrong.
I really hope you can help
tester.php file:
<?php
header('Content-Type: text/html; charset=utf-8');
if (isset($_POST['email']))
{
echo "email: " . $_POST['email'];
echo "
";
echo "password: " . $_POST['password'];
}
else
{
?>
<form method="post">
<input type="text" id="email" name="email" value="切换到中文@gmail.com" />
<br>
<input type="text" id="password" name="password" value="&+=/切/().%&" />
<br>
<input type="submit" />
</form>
<?php
}
Objectice-c HTTP POST execution:
// Get values
NSString *email = @"切换到中文@gmail.com";
NSString *password = @"&+=/切/().%&";
NSLog(@"Before: %@ and %@", email, password);
// Escape tentative 1: fails: % disappears
//email = [email stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet alphanumericCharacterSet]];
//password = [password stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet alphanumericCharacterSet]];
// Escape tentative 2: failed: % disappears, + becomes a space, who knows what else
// email = [email stringByReplacingOccurrencesOfString: @"&" withString: @"%26"];
// password = [password stringByReplacingOccurrencesOfString: @"&" withString: @"%26"];
// Escape tentative 3: % disappears
// NSString *charactersToEscape = @"!*'();:@&=+$,/?%#[]\" ";
// NSCharacterSet *allowedCharacters = [[NSCharacterSet characterSetWithCharactersInString:charactersToEscape] invertedSet];
// email = [email stringByAddingPercentEncodingWithAllowedCharacters:allowedCharacters];
// password = [password stringByAddingPercentEncodingWithAllowedCharacters:allowedCharacters];
// Escape tentative 4: % disappears
/*CFStringRef cf_email = (__bridge CFStringRef)(email);
CFStringRef cf_password = (__bridge CFStringRef)(password);
email = CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,
cf_email,
NULL,
CFSTR("%:/?#[]@!$&'()*+,;="),
kCFStringEncodingUTF8));
password = CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,
cf_password,
NULL,
CFSTR("%:/?#[]@!$&'()*+,;="),
kCFStringEncodingUTF8));*/
// Escape tentative 5: password becomes "(null)"
/*email = [email stringByReplacingOccurrencesOfString: @"%" withString: @"%25"];
email = [email stringByReplacingOccurrencesOfString: @"&" withString: @"%26"];
email = [email stringByReplacingOccurrencesOfString: @"+" withString: @"%2b"];
password = [password stringByReplacingOccurrencesOfString: @"%" withString: @"%25"];
password = [password stringByReplacingOccurrencesOfString: @"&" withString: @"%26"];
password = [password stringByReplacingOccurrencesOfString: @"+" withString: @"%2b"];*/
// Execute HTTP request
NSString *postData = [NSString stringWithFormat:@"email=%@&password=%@", email, password];
NSURLSessionConfiguration *sessionConfiguration = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *session = [NSURLSession sessionWithConfiguration:sessionConfiguration];
NSURL *url = [NSURL URLWithString:@"http://localhost:8080/tester.php"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
request.HTTPBody = [postData dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPMethod = @"POST";
NSURLSessionDataTask *postDataTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
// Print response
NSLog([[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]);
}];
[postDataTask resume];
Result if I am using the HTML form (exactly what I have inputted in the form):
email: 切换到中文@gmail.com password: &+=/切/().%&
What I get from the objective c code (some chars disappear), one of the last tests:
2016-09-29 21:28:59.519 test[44752:2438179] Before: 切换到中文@gmail.com (15) and &+=/切/().%& (11)
2016-09-29 21:28:59.705 test[44752:2438721] email: 切换到中文@gmail.com password: &+=/切/().&
This is the way I do. It worked pretty well with everything I tried. Firstly, you need to add that function to NSString:
@implementation NSString (NSStringWebStructure)
-(NSString*)stringToWebStructure
{
NSString* webString = [self stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
webString = [webString stringByReplacingOccurrencesOfString:@"&" withString:@"%26"];
webString = [webString stringByReplacingOccurrencesOfString:@"?" withString:@"%3F"];
return webString;
}
@end
Now you need the request functions:
-(NSString*)launchURL:(NSURL*)url withPostString:(NSString*)post
{
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:postData];
NSError *error = nil;
NSHTTPURLResponse *response = nil;
NSData *urlData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
if (response.statusCode >= 200 && response.statusCode < 300)
{
NSString *responseData = [[NSString alloc] initWithData:urlData encoding:NSUTF8StringEncoding];
if (responseData.length > 0) return responseData;
}
else if (error) return [error description];
return nil;
}
-(NSString*)launchURL:(NSURL*)url withPostValues:(NSDictionary*)postDict
{
NSArray* postKeys = postDict.allKeys;
NSMutableArray* postLines = [[NSMutableArray alloc] init];
for (NSString* key in postKeys)
{
[postLines addObject:[NSString stringWithFormat:@"%@=%@",key,[postDict[key] stringToWebStructure]]];
}
return [self launchURL:url withPostString:[postLines componentsJoinedByString:@"&"]];
}
And considering your example, you would just need to do that:
NSString *email = @"切换到中文@gmail.com";
NSString *password = @"&+=/切/().%&";
NSURL *url = [NSURL URLWithString:@"http://localhost:8080/tester.php"];
NSDictionary* postValues = @{@"email":email, @"password": password};
NSString* response = [self launchURL:url withPostValues: postValues];
NSLog(@"%@",response);
stringByAddingPercentEscapesUsingEncoding:
was deprecated in macOS 10.11, but if you are going to support old macOS versions, like I do, this is a functional method (tested from macOS 10.6 to macOS 10.12).