如果INT等于3,5,8,10,13,15（等）

I want to have an if statement in PHP to calculate if an INT equals only certain numbers. The pattern would go like: 3, 5, 8, 10, 13, 15, 18, 20 etc. It adds 3, then 2, repeating. The pattern is consistent with the last digit (3,5,8,0), but I don't want to include the first 0.

I could do it this way, but it could go on forever...

if($int == 3 || $int == 5 || $int == 8 || $int == 10 ....)
{
    //do stuff
}

This way also does multiples of 3...

if ($int % 3 == 0)
{
    //do stuff
}

But doesn't do the pattern I want. What's the right way of doing this?

You can do it like this.

Get the remainder of the division by 10 and then check for 0, 3, 5 or 8.

if ($int > 0) {
  $int = $int % 10;
  if ($int == 0 || $int == 3 || $int == 5 || $int == 8)
  {
      //do stuff
  }
}

function check($t) {
    $mod = $t % 10;
    if ($mod == 0 || $mod == 3 || $mod == 5 || $mod == 8)
        echo $t;
}
$arr = array(3, 6, 8, 10, 20, 13, 15, 19);
array_map('check', $arr);