PHP - 如何从shell_exec输出中获取参数

I need to get SSL certificate details (like expiry date, Issuer) of a domain. So for that I ran the following commands from PHP file.

ssl.php

$cdates= shell_exec('openssl s_client -connect example.com:443 2>/dev/null | openssl x509 -noout -dates');
$issuer= shell_exec('openssl s_client -connect example.com:443 2>/dev/null | openssl x509 -noout -issuer');
echo "$cdates";
echo "$issuer";

Getting the following output:

notBefore=Dec 10 11:54:23 2014 GMT notAfter=Mar 10 00:00:00 2015 GMT

issuer= /C=US/O=Google Inc/CN=Google Internet Authority G2 

Now my question is how can I get the parameters from the variables?

For example I need to get CN value (Google Internet Authority G2) from $issuer variable.

So Is there any command/function exists for that or I need to use regular expressions to extract CN from the string?

Any suggestions would be much appreciated.

Seems like this would be a cleaner approach (using phpseclib):

<?php
include('File/X509.php');

$x509 = new File_X509();
$cert = $x509->loadX509(shell_exec('openssl s_client -connect example.com:443 2>/dev/null'));

print_r($x509->getIssuerDNProp('CN'));
?>