如何使用LIKE数组和whereIn来检索Laravel中的雄辩行

I have an array

//dynamically generated. dynamic number of elements
$keywords = ['google', 'youlense'];

For a exactly matching values of $keywork mapping to row in content column, i can do following:

$result = \App\Table::where(function($query){
    $query->whereIn('content', $keywords);
});

and the result would be somewhat

select * from tables where content IN ('google', 'youlense');

but I want to use LIKE operator so the result may be like

select * from tables where content LIKE ('%google%', '%youlense%');

I know that is not allowed in mysql but can some one recommend a simple and clean technique to handle this

You can simply use orWhere method for every keyword and it will equivalent for whereIn. The code will look like:

$result = \App\Table::where(function($query){
    $query->orWhere('content', 'LIKE', '%google%')
          ->orWhere('content', 'LIKE', '%youlense%')
          -> and so on;
});

$result = \App\Table::where(function($query) use($keywords){
    foreach($keywords as $keyword) {
        $query->orWhere('content', 'LIKE', "%$keywords%")
    }
});

Note: gotten query can work very slowly.

You can write a function that will basically do the following :

public function searchByKeywords(array $keywords = array()){
    $result = \App\Table::where(function($query) use ($keywords){
         foreach($keywords as $keyword){
              $query = $query->orWhere('content', 'LIKE', "%$keyword%");
         }
         return $query;
    });
    return $result->get(); // at this line the query will be executed only
                           // after it was built in the last few lines
}